Respuesta :

Two solutions were found :

u ≥ 2
u ≤ 0

The solution of the given inequality 8(u + 8) ≥ 8u+8 is true for all u.

We have given inequality 8(u + 8) ≥ 8u+8

What is inequality?

A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.

Expand 8(u + 8)

[tex]8u+64\ge \:8u+8[/tex]

Subtract 64 from both sides

[tex]8u+64-64\ge \:8u+8-64[/tex]

Simplify given term

[tex]8u\ge \:8u-56[/tex]

Subtract 8u from both sides

[tex]8u-8u\ge \:8u-56-8u[/tex]

Simplify it

[tex]0\ge \:-56[/tex]

Therefore the solution is true for all u.

To learn more about the inequality visit:

https://brainly.com/question/24372553