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For the following exercises, use the table of values that represent points on the graph of a quadratic function. By determining the vertex and axis of symmetry, find the general form of the equation of the quadratic function.

For the following exercises use the table of values that represent points on the graph of a quadratic function By determining the vertex and axis of symmetry fi class=

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Answer:

y = x² + 2x + 1

Step-by-step explanation:

Same y value at x = -2 & x = 0

So line of symmetry is at:

x = (-2+0)/2

x = -1

Vertex: (-1,0)

y = a(x - -1)² + 0

y = a(x + 1)²

At x = 1, y = 4

4 = a(1 + 1)²

4 = 4a

a = 1

y = (x + 1)²

y = x² + 2x + 1

abidemiokin

The general form of the equation of the quadratic function is x² + 2x + 1

The formula expressing the equation of the quadratic function will be expressed as:

y = a(x -h)² + k

From the table shown, we can see that the y-values are the same at where x = -2 and 0

Get the line of symmetry:

[tex]x =\frac{-2+0}{2}\\x=\frac{-2}{2} \\x=-1[/tex]

We can see that when x = -1, y = 0. Hence the vertex will be at (-1, 0)

h = -1

k = 0

Substitute into the formula y = a(x -h)² + k

y = a(x -(-1))² + 0

y = a(x+1)²

From the table at where x = 1, y = 4. On substituting to get "a" we have:

4 = a(1+1)²

4 = 4a

a = 1

Get the required quadratic function by substituting the parameters into the general formula as shown:

y = a(x -h)² + k

y = 1(x +1)² + 0

y = (x+1)²

y = (x+1) (x+1)

y = x² + x +x + 1

y = x² + 2x + 1

Hence the general form of the equation of the quadratic function is x² + 2x + 1

Learn more here: https://brainly.com/question/16842393

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