Second last question what is the area of this compound shape?

Answer:
43.13 yd squared
Step-by-step explanation:
This is a figure composed of a semicircle and a right triangle.
Triangle:
The area of a triangle is denoted by A = (1/2) * B * h, where b is the base and h is the height. Here, the base is actually also the radius of the semicircle, which is 4. The height is 9. Plug these in: A = (1/2) * 4 * 9 = 36/2 = 18 yd squared.
Semicircle:
The area of a semicircle is denoted by A = [tex](1/2)\pi r^{2}[/tex], where r is the radius. Here the radius is 4. So: A = [tex](1/2)\pi *4^{2}=8\pi[/tex] ≈ 25.13 yd squared.
Adding these up: 18 + 25.13 = 43.13 yd squared
Hope this helps!
Answer:
43.12 yd²
Step-by-step explanation:
Semicircle + triangle
½×pi×r² + ½×b×h
½(3.14)(4²) + ½(4)(9)
43.12 yd²