What is the length of a diagonal of a cube with a side length of 6 inches?

Answer:
d = 6√3 inches ≈ 10.40 inches
Step-by-step explanation:
d² = a² + c²
= 36 + 72
= 108
d = √108
= √3×36
= √3×6²
= 6√3 inches
= 6×1.73 inches
= 10.38 inches
≈ 10.40 inches
Answer:
10.4 inches
Step-by-step explanation:
To find the length of the diagonal through the cube, we use the Pythagorean theorem again with legs sqrt(72) and 6, looking for the hypotenuse
a^2 + b^2 = c^2
6^2 + (sqrt(72)^2) = c^2
36 +72 = c^2
108 = c^2
Take the square root of each side
sqrt(108) = sqrt(c^2)
sqrt(108) = c
10.39230485 =c
Rounding to the nearest tenth
10.4 = c