On a coordinate plane, a triangle has points A prime (1, 2), B prime (3, negative 3), C prime (negative 1, negative 3). Triangle ABC was translated according to the rule T4.5, –6.2(x, y) to form A’B’C’ as shown. What are the coordinates of point C of the pre-image?

Respuesta :

AP3623

Answer:

A'(5.5, -4.2), B'(7.5, -9.2), C'(3.5, -3.2)

Step-by-step explanation:

I really do hope I understood you correctly. I figured that the rule would have to be added to each point. If those are wrong, try subtracting the rule.

Again, I'm not trying to take your points and leave you with a wrong answer. I really did give it my best.

The coordinate of the point C of the pre-image will be (-5.5, 5.2).

What is a transformation of geometry?

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Translation does not change the size and shape of the geometry. But change the location of the shape.

On a coordinate plane, a triangle has points A' (1, 2), B' (3, -3), C' (-1, -3).

Triangle ABC was translated according to the rule [tex]\rm T_{4.5, -6.2}[/tex] (x, y) to form A’B’C’ as shown.

Then the rule will be given as,

(x, y) → (x + 4.5, y – 6.2)

Let the coordinate of the point C will be (h, k). Then the transformation is given as,

(–1, –3) → (h + 4.5, k – 6.2)

Then the value of h will be

–1 = h + 4.5

h = –1 – 4.5

h = –5.5

Then the value of k will be

–3 = k – 6.2

k = –1 + 6.2

k = 5.2

Then the coordinate of the point C of the pre-image will be (-5.5, 5.2).

More about the transformation of geometry link is given below.

https://brainly.com/question/22532832

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