Answer:
0.417 m
Explanation:
In order to calculate the molality of a solution prepared by dissolving 10.0 g of NaCl in 600g of water, we need to follow a series of steps.
Step 1: Calculate the moles of NaCl (solute)
The molar mass of NaOH is 40.00 g/mol. The moles corresponding to 10.0 grams are:
[tex]10.0 g \times \frac{1mol}{40.00g} = 0.250mol[/tex]
Step 2: Convert the mass of water (solvent) to kilograms.
We will use the relation 1 kg = 1000 g.
[tex]600g \times \frac{1kg}{1000g} = 0.600kg[/tex]
Step 3: Calculate the molality of the solution
We use the definition of molality.
[tex]m = \frac{moles\ of\ solute}{kilograms\ of\ solvent} =\frac{0.250mol}{0.600kg} = 0.417 m[/tex]
