Answer:
The rock reaches a maximum height of 442.225 m and was thrown at a speed of 93.1 m/s
Explanation:
Vertical Launch
The rock is launched up with a certain speed vo, it reaches its highest point at a height h when the speed is zero, and then it stars a free-fall motion until it hits the ground at time t.
The maximum height is given by
[tex]\displaystyle h=\frac{g\cdot t^2}{2}[/tex]
The rock takes the same time to reach this point as to return to the ground, thus we can calculate the maximum height
[tex]\displaystyle h=\frac{9.8\cdot 9.5^2}{2}=442.225\ m[/tex]
The rock was thrown up at a speed
[tex]v_o=gt=9.8\cdot 9.5=93.1 \ m/s[/tex]
