Given:
Given that the area of the rectangle is [tex]2.48 \times 10^{12} \ cm^2[/tex]
The length of the rectangle is [tex]6.2 \times 10^6 \ cm[/tex]
We need to determine the perimeter of the rectangle.
Width of the rectangle:
The width of the rectangle can be determined using the formula,
[tex]Area = length \times width[/tex]
Substituting the values, we have;
[tex]2.48 \times 10^{12}=6.2 \times 10^6 \times width[/tex]
Dividing both sides of the equation by [tex]6.2 \times 10^4[/tex], we get;
[tex]0.4 \times 10^6=width[/tex]
Thus, the width of the rectangle is [tex]0.4 \times 10^6 \ cm[/tex]
Perimeter of the rectangle:
The perimeter of the rectangle can be determined using the formula,
[tex]P=2(l+w)[/tex]
Substituting the values, we get;
[tex]P=2[(6.2 \times 10^6)+(0.4 \times 10^6)][/tex]
[tex]P=2(6.6 \times 10^6)[/tex]
[tex]P=13.2 \times 10^6 \ cm[/tex]
Thus, the perimeter of the rectangle is [tex]13.2 \times 10^6 \ cm[/tex]
