Answer:
 a.  2, 4, 8, 14, 22, 32
 b.  5, 7, 11, 17, 25, 35
 c.  16, 18, 22, 28, 36, 46
Step-by-step explanation:
a. Add each of the first differences to the previous term.
 first term: 2 . . . (given)
 second term: 2 +2 = 4
 third term: 4 +4 = 8
 fourth term: 8 +6 = 14
 fifth term: 14 +8 = 22
 sixth term: 22 +10 = 32
The first 6 terms of the sequence are 2, 4, 8, 14, 22, 32.
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b. If the first term is n, then the second term is n+2, and their sum is ...
 n +(n+2) = 12
 n = (12 -2)/2 = 5 . . . . solve for n
The first 6 terms of the sequence are 5, 7, 11, 17, 25, 35.
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c. You may have noticed from the above that the 5th term is 20 more than the first term. For this sequence, the first term will be 36 -20 = 16.
The first 6 terms of the sequence are 16, 18, 22, 28, 36, 46.