Respuesta :
Answer:
1. -4
2. +1
3. 0
4. +4
5. -2
6. +1
7. -2
reduced = H
oxidized = O
Explanation:
Know oxidation rules.
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The oxidation numbers of the atoms of the specified elements in each of the given atoms are;
1) -4
1) -42) +1
1) -42) +13) 0
1) -42) +13) 04) +4
1) -42) +13) 04) +45) -2
1) -42) +13) 04) +45) -26) +1
1) -42) +13) 04) +45) -26) +17) -2
1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = C
1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = CAtom reduced = O
1) C in CH4
To get the oxidation number of C;
Oxidation state of hydrogen atom is +1 and so if the oxidation state of C is x, then we have;
x + 4(+1) = 0
x + 4 = 0
x = -4
2) H in CH4
Oxidation state on Carbon atom in this case is -4. Thus;
-4 + 4x = 0
4x = 4
x = +1
3) O in O2
This is oxygen gas that exists in it's free state and as such oxidation number is 0.
4) C in CO2
Oxidation state of O here is -2. Thus;
x + 2(-2) = 0
x - 4 = 0
x = +4
5) O in CO2
Oxidation state of C is +4 here. Thus;
4 + 2x = 0
2x = -4
x = -4/2
x = -2
6) H in H2O
Oxidation state of oxygen here is -2. Thus;
2x - 2 = 0
2x = 2
x = 2/2
x = +1
7) O in H2O
Oxidation state of hydrogen here is +1. Thus;
2(1) + x = 0
x = -2
Finally, oxidation number of carbon increased, then it is the atom that was oxidized while the atom reduced is the Oxygen atom.
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