By one estimate, 3% of all Siberian Husky puppies are born with two different colored eyes (called heterochromia iridum). For random samples of 50 Siberian Husky puppies, what are the mean and standard deviation of the number of puppies that will have two different colored eyes?

A sampling technique of random sampling is one where each sample has an equal chance of being selected, and the calculation can be defined as follows:

Random samples:

Siberian Huskies have 2 distinct hues of eyes as just a percentage.

⇒p = 3% = 0.03

The size of a sample is n = 50.

A mean and standard deviation of several puppies with two distinct colored eyes must be established.
Either the puppies will have two distinct colored eyes or they will not have two different colored eyes.
In this instance, your sample size is fixed at 50.
The puppy's having different coloured irises is self-contained from other puppies, implying that the challenges are self-contained.
In this scenario, the likelihood of success is set at 3 percent.
Since this situation meets all four characteristics of a binomial experiment, we'll answer this question with the binomial experiment formula.

The average number is [tex]\mu[/tex] = np.

The binomial experiment's standard deviation is computed as follows:

[tex]\to \sigma= \sqrt{np(1-p)}[/tex]

We may calculate the following using the values:

[tex]\to \sigma= \sqrt{50 \times 0.03 \times (0.97)}= 1.206[/tex]

Find out more about the random samples here:

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