Answer : The new volume when the temperature is changed to 40 K and the pressure is changed to 1.2 atm is, 0.17 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas at STP = 1 atm
[tex]P_2[/tex] = final pressure of gas = 1.2 atm
[tex]V_1[/tex] = initial volume of gas at STP = 1.4 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas at STP = 273 K
[tex]T_2[/tex] = final temperature of gas = 40 K
Now put all the given values in the above equation, we get:
[tex]\frac{1atm\times 1.4L}{273K}=\frac{1.2atm\times V_2}{40K}[/tex]
[tex]V_2=0.17L[/tex]
Therefore, the new volume when the temperature is changed to 40 K and the pressure is changed to 1.2 atm is, 0.17 L
