Answer:
Explanation:
1. Balanced chemical equation
- Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)
2. Convert 39.5g of Fe₂O₃ into moles
- #moles = mass in grams / molar mass
- molar mass of Fe₂O₃ = 159.69 g/mol
- #moles = 39.5g / 159.69g/mol = 0.24735 mol
3. Moles of CO
i) Mole ratio
ii) Set a proportion
- 3 mol CO / 1 mol Fe₂O₃ = x / 0.24735 mol Fe₂O₃
⇒ x = 0.24735mol Fe₂O₃ × 3mol CO / 1mol Fe₂O₃ = 0.7426 mol CO
4. Grams of CO
- molar mass CO: 28.01g/mol
- mass in grams = #moles × molar mass
- mass = 0.7426mol × 28.01g/mol = 20.8g ← answer
