0.0733L of 3.00 M CH3COOH solution is needed to provide 0.220 mol of CH3COOH.
Explanation:
Molarity, M = moles of the molecule / Liter of solution
Therefore, we can work backwards to find the number of litres of solution, if we are given the number of moles
The values are a given as,
The molarity of the solution =3.00M
The final moles = 0.220 moles.
0.220 mol CH3COOH ( 1L / 3.00 mol CH3COOH) = 0.220/3.00
=0.0733L of solution
The volume of the 3.00 M CH₃COOH solution needed to provide 0.220 mol of CH₃COOH is 73.33 mL
From the question,
We are to determine the volume of the 3.00 M CH₃COOH solution is needed to provide 0.220 mol of CH₃COOH
From the formula
Number of moles = Concentration × Volume
Then, we can write that
[tex]Volume = \frac{Number\ of\ moles}{Concentration}[/tex]
From the given information
Number of moles = 0.220 mol
Concentration = 3.00 M
Putting the parameters into the formula, we get
[tex]Volume = \frac{0.220}{3.00}[/tex]
Volume = 0.07333 L
Volume = 73.33 mL
Hence, the volume of the 3.00 M CH₃COOH solution needed to provide 0.220 mol of CH₃COOH is 73.33 mL
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