Respuesta :
Answer: The mass of [tex]CO_2[/tex] needed is, 0.915 grams.
Explanation : Given,
Mass of [tex]Mg[/tex] = 1.00 g
Molar mass of [tex]Mg[/tex] = 24 g/mol
First we have to calculate the moles of [tex]Mg[/tex].
[tex]\text{Moles of }Mg=\frac{\text{Given mass }Mg}{\text{Molar mass }Mg}[/tex]
[tex]\text{Moles of }Mg=\frac{1.00g}{24g/mol}=0.0417mol[/tex]
Now we have to calculate the moles of [tex]CO_2[/tex]
The balanced chemical equation is:
[tex]2Mg+CO_2\rightarrow 2MgO+C[/tex]
From the balanced reaction we conclude that
As, 2 mole of [tex]Mg[/tex] react with 1 mole of [tex]CO_2[/tex]
So, 0.0417 moles of [tex]Mg[/tex] react with [tex]\frac{0.0417}{2}=0.0208[/tex] moles of [tex]CO_2[/tex]
Now we have to calculate the mass of [tex]CO_2[/tex]
[tex]\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2[/tex]
Molar mass of [tex]CO_2[/tex] = 44 g/mole
[tex]\text{ Mass of }CO_2=(0.0208moles)\times (44g/mole)=0.915g[/tex]
Therefore, the mass of [tex]CO_2[/tex] needed is, 0.915 grams.
