Answer:
a is formed above the eutecoid temperature as well (pro-eutecoid ferrite)
Thus ferrite is proeutectoid phase since 0.45 wt% C is less than 0.76 wt% C
b  7.487 kg of total ferrite
 0.51273 kg of total cementite
c 4.62703 kg of total pearlite
 3.35135 kg of total proeutectoid ferrite
Explanation:
a) What is the proeutectoid phase
is formed above the eutecoid temperature as well (pro-eutecoid ferrite)
Thus ferrite is proeutectoid phase since 0.45 wt% C is less than 0.76 wt% C
(b) How many kilograms each of total ferrite and cementite form
Wα = CFe3C - Co   = 6.70 - 0.45   = 0.93590
     CFe3C - Cα     6.70 - 0.022
Which corresponds to 0.93590 x 8.0 kg = 7.487 kg of total ferrite
Similarly for total cementite
WCFe3C = Co - Cα      = 0.45 - 0.022   = 0.006409
         CFe3C - Cα     6.70 - 0.022
which corresponds to 0.006409 x 8. 0 kg = 0.51273 kg of total cementite
c) How many kilograms each of pearlite and the proeutectoid phase form?
considering the amount of pearlite and the proeutectoid phase ferrite formed
Wp =  Co¹ - 0.022 = 0.45 - 0.022 = 0.5784
       0.74          0.74
which corresponds to 0.5784 x 8. 0 kg = 4.62703 kg of total pearlite
Wα =  0.76 - 0.45 = 0.41892
       0.74         Â
which corresponds to 0.418.92 x 8. 0 kg = 3.35135 kg of total proeutetcoid ferrite
