Answer:
The specific heat of the metal is 0.466 [tex]\frac{J}{g*C}[/tex]
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
Replacing:
2330 J= c*25 g* 200 °C
Solving:
[tex]c=\frac{2330 J}{25 g* 200 C}[/tex]
c=0.466 [tex]\frac{J}{g*C}[/tex]
The specific heat of the metal is 0.466 [tex]\frac{J}{g*C}[/tex]
A 25 g metal, whose temperature increases 200 °C when absorbing 2330 J, has a specific heat of 0.466 J/g.°C.
A 25 gram (m) metal ball is heated to 200 °C (ΔT) with 2330 Joules (q) of energy.
The specific heat (c) of a substance is the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).
We can calculate the specific heat of the metal using the following expression.
[tex]c = \frac{q}{m \times \Delta T } = \frac{2330J}{25g \times 200 \° C } = 0.466 J/g.\° C[/tex]
A 25 g metal, whose temperature increases 200 °C when absorbing 2330 J, has a specific heat of 0.466 J/g.°C.
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