Respuesta :
Answer:
The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.
Explanation:
Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:
[tex]v=v_0+at\\\\v^2=v_0^2+2ad[/tex]
Dividing the second equation by the first one, we obtain:
[tex]v=\frac{v_0^2+2ad}{v_0+at}[/tex]
And, since [tex]v_0=0[/tex], then:
[tex]v=\frac{2ad}{at}\\\\v=\frac{2d}{t}\\\\v=\frac{2(0.50m)}{0.55s}\\\\v=1.81m/s[/tex]
It means that the velocity at the bottom of the ramp is 1.81m/s.
We could use this data, plus any of the two initial equations, to determine the acceleration:
[tex]v=v_0+at\\\\\implies a=\frac{v}{t}\\\\a=\frac{1.81m/s}{0.55s}\\\\a=3.30m/s^2[/tex]
So the acceleration is 3.30m/s^2.
