solve for x. pls pls pls pls pls pls

Answer:
[tex] smaller \: x = \boxed { - 5} \\ larger \: x = \boxed 2[/tex]
Step-by-step explanation:
[tex]5 {x}^{2} + 15x - 50 = 0 \\ 5( {x}^{2} + 3x - 10) = 0 \\ {x}^{2} + 3x - 10 = 0 \\ {x}^{2} + 5x - 2x - 10 = 0 \\ x(x + 5) - 2(x + 5) = 0 \\ (x + 5)(x - 2) = 0 \\ x + 5 = 0 \: or \: x - 2 = 0 \\ x = - 5 \:or \: x = 2 \\ smaller \: x = \boxed { - 5} \\ larger \: x = \boxed 2[/tex]