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If the pressure of a gas is 100 kPa when the volume is measured to be 500 mL. What pressure would need to be exerted to have the balloon occupy a volume of 400 mL?

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debooxpp

Answer:

p2=125 kpa

Explanation:

Using Boyle's law

p1 x v1 = p2 x v2

p1=100kpa

v1=500ml

p2=?

v2=400ml

p2= (100x500)\400

p2=125 kpa

:)

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