Answer: We will not accept the null hypothesis.
Step-by-step explanation:
Since we have given that
sample size n = 1068
[tex]\hat{p}[/tex] = 48% = 0.48
At 0.01 level of significance, z = - 2.58
Hypothesis are:
[tex]H_0:p=0.5\\\\H_a:p\neq 0.5[/tex]
So, test statistic value would be:
[tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.48-0.50}{\sqrt{\dfrac{0.5\times 0.5}{1068}}}\\\\z=\dfrac{-0.02}{0.0152}\\\\z=-1.315[/tex]
So, test statistic > critical value.
Hence, we will not accept the null hypothesis.