The final temperature will be "275 K". To understand the calculation, check below.
Temperature and Pressure
According to the question,
Pressure, P₁ = 1.00 atm
P₂ = 2.75 atm
Temperature, T₁ = 300 K
Moles, n₁ = 1.00 mol
n₂ = 1.00 + ([tex]\frac{88.0}{44.01}[/tex])
= 3.00 mol
By using the ideal gas equation,
→ [tex]\frac{P_1}{n_1 T_1} = \frac{P_2}{n_2 T_2}[/tex]
or, Temperature, T₂ = [tex]\frac{P_2 n_1 T_1}{n_2 P_1}[/tex]
By substituting the values,
= [tex]\frac{2.75\times 1.00\times 300}{3.00\times 1.00}[/tex]
= 275 K
Thus the above response is correct.
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