Suppose we have two thermometers. One thermometer is very precise but is delicate and heavy (X). We have another thermometer that is much cheaper and lighter, but of unknown precision (Y). We would like to know if we can (reliably) bring the lighter thermometer with us into the field. So, we set up an experiment where we expose both thermometers to 31 different temperatures and measure the temperature with each.
We get the following observations:
x = 0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120
y = 0.02, 3.99, 7.91, 12.03, 16.09, 20.00, 23.98, 28.09, 31.94, 36.03, 40.00, 44.05, 47.95, 52.00, 55.87, 59.90, 63.91, 67.95, 72.11, 76.02, 80.01, 84.10, 88.06, 91.74, 96.02, 99.95, 103.87, 108.01, 111.99, 116.04, 120.03
We want to test if these thermometers seem to be measuring the same temperatures. Let's use the threshold α=0.1.
Answer all questions up to 3 decimals
(a) Write down the appropriate hypothesis tests for β1.
H0: β1(≠ / = / > / <) 1 and Ha: β1( ≤ / = / > / ≠ / ≥ / <) 1.
(b) The test statistic is _____. (Use 2 decimal places)
(c) The p-value is _____. (Use 4 decimal places)

Respuesta :

Answer:

Step-by-step explanation:

(a)   H0: μ_D=0

      Ha: μ_D ≠ 0

b) Find attached the solution

(c)  By technology,

p - value = 0.4437

Hence, the p-value is 0.4437

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Using the paired t test statistic, the value of the test statistic and the Pvalue are 0.78 and 0.444 respectively.

The hypothesis :

  • H0: β1 = 0
  • H0: β1 ≠ 0

For a paired t test ; The test statistic is defined thus :

  • Test statistic = [tex]\frac{\{bar}d}{\frac{S_{d}}{\sqrt{n}}[/tex]

  • Mean of difference, d = x - y = 0.011
  • Standard deviation of sample difference, Sd = 0.079

Substituting the values into the equation :

Test statistic = [tex]\frac{0.011}{\frac{0.079}{\sqrt{31}}} [/tex]

Test statistic = 0.775

The Pvalue can be calculated thus:

  • α = 0.1 ; 2 - tailed test ;

Pvalue = 0.444 (P value calculator).

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