Answer:
Potential energy of the system = 0.099 J
Explanation:
Electrical potential energy for two charge system when zero potential energy is considered at infinitely far
[tex]U=\frac{1}{4\pi\epsilon_0 } \frac{q_1\cdot q_2}{r}[/tex]
[tex]Where, q_1\ & q_2\ are\ magnitude\ of\ charge.\\and\ r\ is\ the\ distance\ between\ the\ charge.\\and\ \frac{1}{4\pi\epsilon_0 } =9\cdot10^9 N m^2C^-2[/tex]
[tex]Given, q_1=q_2 =q_3= 1.05 \cdot10^-6\ C\\and\ r=0.3\ m\\Since\ charges\ are\ placed\ at\ the\ corners\ of\ equilateral\ triangle[/tex]
[tex]U= 3\cdot\frac{1}{4\pi\epsilon_0 } \frac{q_1\cdot q_2}{r}= 3\cdot9\cdot10^9\cdot1.05\cdot10^-6\cdot1.05\cdot10^-6\cdot\frac{1}{0.3}=0.099\ J[/tex]
Hence, potential energy of the system = 0.099 J
