A random sample of 40 PCC students are surveyed about their commuting time. A mean of 24.5 minutes was calculated from the survey. The population standard deviation is known to be 5.8 minutes. Construct a 95% confidence interval for the average commuting time for all PCC students. Round your answer to the nearest tenth of a minute.

Respuesta :

Answer:

[22.7, 26.3]

Step-by-step explanation:

-Given that n=40, mean=24.5 and the standard deviation is 5.8.

-The 95% confidence interval can be calculated as follows:

[tex]CI=\mu\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]

#Substitute the given values to solve for CI:

[tex]CI=\mu\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\\\=24.5\pm1.96\times \frac{5.8}{\sqrt{40}}\\\\\\=24.5\pm 1.8\\\\=[22.7,\ \ \ 26.3][/tex]

Hence, the confidence interval is [22.7, 26.3]