Respuesta :
Answer:
a. They would have a black chick? 25%
b. They would have a white chick? 25%
The probability that a cross between both two erminette chickens would give are:
- black chick - 25%.
- white chick - 25%.
Note the following about erminette chickens:
- In erminette chickens, the allele for black (B) and the allele for white (W) feathers are both codominant.
- Both alleles when present together in an allelic pair will express themselves equally. That is what gives the erminette chickens their black and white feathers mixed together.
Now, let's consider the possibility of two erminette chickens crossing each other, each having a genotype of (BW) that codes for black and white feathers.
The result of the cross has been provided in the attachment below using a Punnett square.
From the cross, the following genotype and phenotype are what we would get:
Probability resulting from the cross:
- 2 BW - 50% would be erminette chick i.e. black and white chicks.
- 1 BB - 25% would be only black chicks.
- 1 WW - 25% would be only white chicks.
Therefore, the probability that a cross between both two erminette chickens would give are:
- black chick - 25%
- white chick - 25%
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