Answer:
c) 0.22
Step-by-step explanation:
Explanation:-
A random sample of 500 army recruits has a mean height of 68 inches with a standard deviation of 2.5 inches.
The sample size 'n' = 500
Given the mean of the sample = 68 inches
Given standard deviation = 2.5 inches
[tex]Margin error = \frac{Z_{\alpha } S.D}{\sqrt{n} }[/tex]
The 95% of confidence interval ∝ = 1.96
[tex]M.E = \frac{1.96 X 2.5}{\sqrt{500} }[/tex]
Margin of error = 0.2191 ≅0.22
Conclusion:-
The Margin of error at 95% of confidence intervals = 0.22
