Answer:
The above equation is a quadratic function whose zeroes are 3 and 12.
Step-by-step explanation:
The general quadratic equation is given by :
[tex]ax^2+bx+c=0[/tex]
It is given that, the zeroes of a quadratic function are 3 and 12. It means they must be factors of it such that,
[tex](x-3)=0\\\\(x-12)=0[/tex]
So, we can write as :
[tex](x-3)(x-12)=0[/tex]
Multiplying both factors,
[tex](x-3)(x-12)=0\\\\x^2-12x-3x+36=0\\\\x^2-15x+36=0[/tex]
So, the above equation is a quadratic function whose zeroes are 3 and 12.
