Answer:
Height of mirror 0.075 m
width of mirror 0.325 m
Explanation:
given data
wide = 1.3 m
high = 0.30 m
driver’s eyes = 0.50 m
rear window = 1.50 m
solution
we take here height / width of the mirror is
height / width = [tex]\frac{h}{w}[/tex] .................1
and
height /width of the window is
height /width = [tex]\frac{h_w}{w_w}[/tex] .................2
and
distance of eye / window by the mirror is
distance of eye / window = [tex]\frac{x_e}{x_w}[/tex] .................3
so here
θ = θi = θr ....................4
and tanθ for vertical is
tanθ = [tex]\frac{h}{x_e}[/tex]
tanθ = [tex]\frac{h_w}{(x_e + x_w)}[/tex] ....................5
so
h = [tex]h_w \times \frac{x_e}{(x_e + x_e)}[/tex] ....................6
put here value and we get
[tex]h = 0.30 \times \frac{0.50}{(0.50 + 1.50)}[/tex]
h = 0.075 m
and
when we take here tanθ for horizontal than it will be
tanθ = [tex]\frac{w}{x_e}[/tex]
tanθ = [tex]\frac{w_w}{(x_e + x_w)}[/tex] .......................7
so
[tex]w = w_w \times \frac{x_e}{(x_e + x_w)}[/tex] ....................8
put here value and we get
[tex]w = 1.3 \times \frac{0.50}{(0.50 + 1.50)}[/tex]
w = 0.325 m
