Answer:
$74,600
Step-by-step explanation:
-Given the probability is 2.5%, mean=$55,000 and standard deviation= $10,000
-We find the z value of 2.5%
[tex]p=P(z>\frac{X-\mu}{\sigma})\\\\1.96=P(z<\frac{X-\mu}{\sigma}}\\\\\\\therefore 1.96=\frac{X-55000}{10000}\\\\\\X=1.96\times 10000+55000\\\\=74600[/tex]
Hence, the minimum amount of income to be in the top 2.5% is $74,600