anonymous190
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Aro diagrams his river rafting trip, estimating the time it will take him to paddle upstream against the current, and then back downstream with the current. His campsite destination is 5.2 miles upstream. Determine how fast Aro can paddle and how fast the river water is moving.

Upstream:

Downstream:

Use the fact that d = rt to write the system of equations that represents the scenario. Let x be the speed of Aro’s paddling and let y be the speed of the river.



Upstream:

5.2 = ()



Downstream:

5.2 = ()

Respuesta :

Answer:

Aro can paddle at a speed of  

5

⇒ 1.56 miles per hour.

 

The river’s speed is  

2.5

⇒ 0.52 miles per hour.

Step-by-step explanation:

i got it wrong so here it is

kamaladhakal909

Answer:

Answer:

The speed of Aro’s paddling and speed of river are 1.561.56 miles per hour and 0.520.52 miles per hour respectively.

Step-by-step explanation:

Given: Aro diagrams his river rafting trip, estimating the time it will take him to paddle upstream against the current, and then back downstream with the current. His campsite destination is 5.2 miles upstream.

Let xx be the speed of Aro's paddling miles per hour

And let yy be the speed of the river miles per hour

Now according to the question,

CaseI:I: Upstream

x-y=1.04 \ \ \ \ \ \ ....(1)x−y=1.04 ....(1)

Case II:II: Downstream

x+y=2.08 \ \ \ \ \ \ ....(2)x+y=2.08 ....(2)

Adding equation (1) and (2) we get,

\begin{gathered}x-y+x+y=1.04+2.08\\\end{gathered}

x−y+x+y=1.04+2.08

\begin{gathered}2x=3.12\\&\ \ \ x=1.56\end{gathered}

2x=3.12

x=1.56

Now substiuting the value of x=1.56x=1.56 in equation (2)

\begin{gathered}1.56+y=2.08\\\end{gathered}

1.56+y=2.08

\begin{gathered}y=2.08-1.56\\y=0.52\end{gathered}

y=2.08−1.56

y=0.52

Hence, the speed of Aro’s paddling is 1.561.56 miles per hour and speed of river is 0.520.52 miles per hour.

For more information:

https://brainly.com/question/17300107?referrer=searchResults

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