Consider a circle whose equation is x2 + y2 + 4x - 6y - 36 = 0. Which statements are true? Check all that apply.
To begin converting the equation to standard form, subtract 36 from both sides.
To complete the square for the x terms, add 4 to both sides.
The center of the circle is at (-2, 3).
The center of the circle is at (4, -6).
The radius of the circle is 6 units.
The radius of the circle is 49 units.

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faithann16 faithann16 · Answer 1 · 2020-04-25T07:30:58+02:00

Answer: •to complete the square for the x terms, add 4 to both sides

•The center of the circle is at (-2,3)

Step-by-step explanation:

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raphealnwobi raphealnwobi · Answer 2 · 2022-03-16T11:13:16+01:00

The center of the circle is (-2. 3) and the radius is 7 units.

The standard equation of a circle is given by:

(x - h)² + (h - k)² = r²

Where (h, k) is the center of the circle and r is the radius

Given:

x² + y² + 4x - 6y - 36 = 0

x² + 4x + y² - 6y = 36

x² + 4x + 4 + y² - 6y + 9 = 36 + 4 + 9

(x + 2)² + (y - 3)² = 7²

The center of the circle is (-2. 3) and the radius is 7 units.

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