Answer : The moles of [tex]H_2SO_4[/tex] are, 2.125 mole.
Explanation : Given,
Molarity of [tex]H_2SO_4[/tex] = 8.500 M
Volume of solution = 250 mL = 0.250 L (1 L = 1000 mL)
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution (in L)}}[/tex]
Now put all the given values in this formula, we get:
[tex]8.500M=\frac{\text{Moles of }H_2SO_4}{0.250L}[/tex]
[tex]\text{Moles of }H_2SO_4=2.125mol[/tex]
Therefore, the moles of [tex]H_2SO_4[/tex] are, 2.125 mole.
