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Byron bought a keyless entry door lock that has the digits 0 through 9 on the keypad. He wants to choose a three-digit entry code. How many different combinations are possible, if the digits can be repeated?

Respuesta :

Answer:

1000

Step-by-step explanation:

We have 10 options for the first digit (0-9, inclusive)

We have 10 options for the second digit, too, because repetition is allowed.

We have 10 options for the third!

So!

10 * 10 * 10 = 1000 :))

Answer:

d

Step-by-step explanation:

The answer is 1,000! For each digit you get 10 options: 0,1,2,3,4,5,6,7,8,9.

So if you were to have ten options for each of the three digits you can enter, you multiply all possibilities together. So 10 times 10 is 100. 100 times ten is 1,000.

(10 x 10 x 10 = 1000)

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