Answer:
[tex]V_2=2.68L[/tex]
Explanation:
Hello,
In this case, we use the Charles' law which allows us to understand the volume-temperature behavior as gas has as a directly proportional relationship:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
Whereas the temperature must be in absolute units such as Kelvin. Hence, solving for the volume at 43.0 °C, we obtain:
[tex]V_2=\frac{V_1T_2}{T_1}=\frac{2.50L*(43.0+273.15)K}{(22.0+273.15)K} \\\\V_2=2.68L[/tex]
Best regards.