Respuesta :
Answer: 156 K
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 450 torr
[tex]P_2[/tex] = final pressure of gas = 800 torr
[tex]V_1[/tex] = initial volume of gas = 1.80 L
[tex]V_2[/tex] = final volume of gas = [tex]\frac{1}{3}\times 1.80L=0.60L[/tex]
[tex]T_1[/tex] = initial temperature of gas = [tex]-10^oC=273-10=263K[/tex]
[tex]T_2[/tex] = final temperature of gas = ?
Now put all the given values in the above equation, we get:
[tex]\frac{450\times 1.80}{263}=\frac{800\times 0.60}{T_2}[/tex]
[tex]T_2=156K[/tex]
Thus the final temperature will be 156 K
