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Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the discharge of a 1.89 F capacitor charged to 59.9 kV . Rosa rightly reckons that she can enhance the effect of each laser pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose dielectric constant is 435 , with one possessing a dielectric constant of 923 . Find the electric potential energy of the original capacitor when it is charged.

Respuesta :

Answer:

Energy stored in original capacitor is [tex]32.89\times 10^6J[/tex]

Explanation:

We have given capacitance [tex]C=1.89F[/tex]

Capacitor is charged by [tex]V=59.9KV=59.9\times 10^3volt[/tex]

We to find energy stored in the capacitor when it is charged

Energy stored in original capacitor is equal to

[tex]E=\frac{1}{2}CV^2[/tex]

[tex]E=\frac{1}{2}\times 1.89\times (5.9\times 10^3)^2=32.89\times 10^6J[/tex]

So energy stored in original capacitor is [tex]32.89\times 10^6J[/tex]

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