Answer:
(a) [tex]F = -4.01 * 10^{-15} N[/tex]
(b) [tex]a = 4.40 * 10^{15} m/s^2[/tex]
Explanation:
Parameter given:
Electric field, E = [tex]2.5 * 10^4 N/C[/tex]
(a) Electric force is given (in terms of electric field) as a product of electric charge and electric field.
Mathematically:
[tex]F = qE[/tex]
Electric charge, q, of an electron = [tex]- 1.602 * 10^{-19} C[/tex]
[tex]F = -1.602 * 10^{-19} * 2.5 * 10^4\\\\\\F = -4.01 * 10^{-15} N[/tex]
(b) This electrostatic force causes the electron to accelerate with an equivalent force:
F = -ma
where m = mass of an electron
a = acceleration of electron
(Note: the force is negative cos the direction of the force is opposite the direction of the electron)
Therefore:
[tex]-ma = -4.01 * 10^{-15} N\\\\\\a = \frac{-4.01 * 10^{-15}}{-m}[/tex]
Mass, m, of an electron = [tex]9.11 * 10^{-31} kg[/tex]
=> [tex]a = \frac{-4.01 * 10^{-15}}{-9.11 * 10^{-31}}\\\\\\a = 4.40 * 10^{15} m/s^2[/tex]
The acceleration of the electron is [tex]4.40 * 10^{15} m/s^2[/tex]
