Answer: [tex]943\dfrac{1}{4}\text{ sq. yds}[/tex]
Step-by-step explanation:
Given , A farmer plowed a rectangular section of land for a new crop.
Dimensions of the section is given by :-
Length by width = [tex]24\dfrac{1}{2}\text{ yd by }38\dfrac{1}{2}\text{ yd}[/tex]
Since , the area of a rectangle = length x width
Then, the total area in yards of plowed section of land will be:
[tex]24\dfrac{1}{2}\times38\dfrac{1}{2}\text{ sq. yds}\\\\=\dfrac{2(24)+1}{2}\times\dfrac{2(38)+1}{2}\text{ sq. yds}\\\\=\dfrac{49}{2}\times\dfrac{77}{2}\text{ sq. yds}\\\\=\dfrac{3773}{4}\text{ sq. yds}\\\\=943\dfrac{1}{4}\text{ sq. yds}[/tex]
Hence, the total area in yards of plowed section of land = [tex]943\dfrac{1}{4}\text{ sq. yds}[/tex]
