Respuesta :
Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
Explanation:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
95% confidence for µ, the average number of times a horse races
[tex](x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )[/tex]
[tex](15.3- 2.064 \frac{6.8}{\sqrt{25} } , 15.3 + 2.064\frac{6.8}{\sqrt{25} } )[/tex]
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
Conclusion:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
