Answer:
[tex]V_2=564.17mL[/tex]
Explanation:
Hello,
In this case,
One uses the Boyle's law that allows us to understand the pressure-volume behavior at constant temperature as an inversely proportional relationship:
[tex]P_1V_1=P_2V_2[/tex]
Thus, solving for the volume at the new 88.2 kPa pressure, one obtains:
[tex]V_2=\frac{P_1V_1}{P_2} =\frac{104.1kPa*478mL}{88.2kPa} \\\\V_2=564.17mL[/tex]
Best regards.