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If a woman who is a carrier for Tay-Sachs has children with a man who is not a Tay-Sachs carrier, what is the probability that one of their children will be a carrier for Tay-Sachs? (Sketch a Punnett square to help you find the correct answer.)

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khubaid

Answer:

50%

Explanation:

Suppose we denoted Tay-Sachs with (TT)

Tay-Sachs carrier (Tt)

No Tay-Sachs (tt)

Mother is Tay-Sachs carrier: Tt

Father has no Tay-Sachs: tt

According to Punnett square: Tt x tt

                      t                        t

T                   Tt                       Tt

t                     tt                        tt

So, there will be 50% chance of being carrier for Tay-Sachs to their offspring.

                     

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