Respuesta :
Answer:
1st term = a = 34
2nd term = a + d = 34+8 = 42
3rd term = a +2d = 34+2(8) = 50
= 34,42,50
Step-by-step explanation:
Given;
Common difference d = 8
Sum of three consecutive terms = 126
Using the arithmetic progression AP nth term formula;
nth term = a + (n-1)d
Where;
a = first term
d = common difference
So,
1st term = a
2nd term = a + d
3rd term = a + 2d
Sum of the three consecutive terms;
a + a+d + a+2d = 3a + 3d
Equating to the given value;
3a + 3d = 126
3a + 3(8) = 126 (d=8 given)
3a = 126 - 24
3a = 102
a = 102/3 = 34
Therefore,
1st term = a = 34
2nd term = a + d = 34+8 = 42
3rd term = a +2d = 34+2(8) = 50
Answer: 34, 42, 50
Step-by-step explanation:
Let the first term be a
Second term will be a+d
Third term will be a+2d
a+a+d+a+2d= 126
3a+3d = 126
Recall that the common difference (d) is 8.
3a+3d= 126
3a+(3×8) = 126
3a+24 = 126
3a= 126 - 24
3a = 102
a = 102/3
a= 34
First term is 34
Second term will be a+d
= 34+8 = 42
Third term will be a+2d
= 34 + (2×8)
= 34+16
= 50
