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Your friend has been given a laser for her birthday. Unfortunately, she did not receive a manual with it and so she doesn't know the wavelength that it emits. You help her by performing a double-slit experiment, with slits separated by 0.18 mmmm. You find that two adjacent bright fringes are 4.9 mmmm apart on a screen 1.4 mm from the slits.

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whitneytr12

Answer:

[tex]\lambda=630 nm[/tex]        

Explanation:

The equation of the fringe in a double slit experiment is given by:

[tex]y=\frac{m\lambda D}{d}[/tex] (1)

here:

  • y is the distance between bright fringes (two adjacent bright fringes distance = 4.9 mm).
  • m is a natural number, related to the bright fringes in a diffraction pattern, in our case we use m=1
  • D is the distance between the screen and the double slit (D=1.4 m)
  • d is the distance between the slits (d=0.18 mm)
  • λ is the wave length of the laser.

Therefor we just need to solve the equation (1) for λ:

[tex]\lambda=\frac{d*y}{D}[/tex]

[tex]\lambda=\frac{0.00018*0.0049}{1.4}[/tex]            

[tex]\lambda=6.3*10^{-7}m[/tex]      

[tex]\lambda=630 nm[/tex]        

I hope it helps you!                              

mavila18

Answer:

6.3*10^-7m

Explanation:

to find the wavelength of the laser you can use the following formula:

[tex]y=\frac{m\lambda D}{d}[/tex]

y: height from the center of the screen to a fringe

m: order of the fringe

D: distance to the screen = 1.4m

d: distance between slits = 0.18mm

you know the separation of two fringes. Hence, you can use two consecutive fringes to find the wavelength in the following way:

[tex]\Delta y=\frac{m\lambda D}{d}-\frac{(m-1)\lambda D}{d}=\frac{\lambda D }{d}\\\\\lambda=\frac{\Delta y d}{D}=\frac{(4.9*10^{-3}m)(0.18m*10^{-3}m)}{1.4m}=6.3*10^{-7}m[/tex]

hence, the walength is 6.3*10^-7m

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