Answer:[tex]sin(B)=\frac{3}{5}[/tex]
Step-by-step explanation:
We are given that a triangle ABC is a Right Angled Triangle. The side AB is hypotenuse, so the angle opposite to side AB which will be angle C is a Right Angle (measures 90 degrees)
We have the side length of all 3 sides. Based on this information, we can construct a triangle with given measures. The triangle is shown in the attached image.
We have to find the value of Sin(B). Sin of an angle is defined as:
[tex]sin(\theta)=\frac{\text{Opposite Side}}{\text{Hypotenuse}}[/tex]
The side opposite to angle B is AC with a length of 3 and hypotenuse is side AB with length 5. So Sin of angle B would be:
[tex]sin(B)=\frac{3}{5}[/tex]
