Answer:
The student will swing to a height of 61.25 cm.
Explanation:
Given that,
Mass of the student, m = 80 kg
Speed of student, v = 3.5 m/s
The student running at this speed grabs a rope that is hanging vertically. In the whole process, the energy of the system remains conserved. So, using conservation of energy to find the height reached by the student. So,
[tex]\dfrac{1}{2}mv^2=mgh[/tex]
h is height reached by the student
[tex]h=\dfrac{v^2}{2g}\\\\h=\dfrac{(3.5)^2}{2\times 10}\\\\h=0.6125\ m\\\\h=61.25\ cm[/tex]
So, the student will swing to a height of 61.25 cm.
