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A 2.0-kilogram block sliding down a ramp from a height of 3.0 meters above the ground
reaches the ground with a kinetic energy of 50. joules. The total work done by friction on the
block as it slides down the ramp is approximately
(1) 6 J
(2) 9 J
(3) 18 J
(4) 44 J

Respuesta :

dishapatel

Answer:

9j

Explanation:

onyebuchinnaji

The total work done by friction on the block as it slides down the ramp is 44 J.

The given parameters;

  • mass of the block, m = 2 kg
  • height of the ramp, h = 3.0 m
  • kinetic of the block, K.E = 50 J

The work done by friction is the change in the mechanical energy of block;

[tex]W = \Delta E\\\\W = K.E - P.E\\\\W = 50 \ - \ (2\times 3)\\\\W = 50 - 6\\\\W = 44 \ J[/tex]

Thus, the total work done by friction on the block as it slides down the ramp is 44 J.

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