Answer:
The answer to your question is the letter A.C₈H₈O₃
Explanation:
Data
Carbon = 63.15%
Oxygen = 31.55%
Hydrogen = 5.30%
Process
1.- Express the percents as grams
Carbon = 63.15g
Oxygen = 31.55g
Hydrogen = 5.30g
2.- Convert the grams to moles
Carbon
MM = 12 12 g of C ------------ 1 mol
63.15 g ------------- x
x = 63.15/12
x = 5.263
Hydrogen
MM = 1 1 g of H ------------- 1 mol
5.3 g of H ----------- x
x = (5.3 x 1)/1
x = 5.3 g
Oxygen
MM = 16 16 g of O ------------- 1 mol
31.55 g of O ---------- x
x = (31.55 x 1)/16
x = 1.972
2.- Divide each result by the lowest number of moles
Carbon = 5.263/1.972 = 2.66
Hydrogen = 5.3/1.972 = 2.6
Oxygen = 1.972/1.972 = 1
3.- Write the empirical formula
C₂.₆₆H₂.₆₆O₁
-But do not use decimals so, multiply by three of the formula
C₇.₉₈H₇.₉₈O₃ or C₈H₈O₃
