Answer:
1/3
Step-by-step explanation:
you take the probability divide by the tossing times
The probability that the sequence contains exactly two heads will be 0.2344.
Bernoulli's trials are those trials which end up randomly either on success (with probability p) or on failures (with probability 1- p = q (say))
The probability that out of n trials, there'd be x successes is given by
[tex]\rm P(X =x) = \: ^nC_xp^x(1-p)^{n-x}[/tex]
A fair coin is tossed six times and the sequence of heads and tails is recorded.
The probability that the sequence contains exactly two heads will be
n = 6
p = q = 1/2
Then the probability will be
P(x = 2) = ⁶C₂ (1/2)² (1/2)⁴
P(x = 2) = 0.2344
Learn more about binomial distribution here:
https://brainly.com/question/13609688
#SPJ2
