Answer:
q2 = 9.02*10^{-4}C
Explanation:
To find the value of the other charge you use the Coulomb's law:
[tex]F=k\frac{q_1q_2}{r^2}[/tex]
k: Coulomb's constant = 8.98*10^{9}Nm^2/C^2
q1: charge 1 = 55*10^{-6}C
r: distance between charges = 90cm = 0.9m
F: electric force = 550N
By doing q2 the subject of the formula and replacing you obtain:
[tex]q_2=\frac{r^2F}{kq_1}=\frac{(0.9m)^2(550N)}{(8.98*10^9Nm^2/C^2)(55*10^{-6}C)}=9.02*10^{-4}C[/tex]
hence, the value of the other charge q2 is 9.02*10^{-4}C
